How Will You Bring About The Following Conversions ? ( Part-2)

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(VI) Ethanol To Ethyl fluoride (VII) Bromomethane To Propanone (VIII) But-1-ene To But-2-ene (IX) 1- Chlorobutane To n-Octane (X)Benzene To Biphenyl Other Links :- You May Also Visit - 1)  https://chemiask.blogspot.com/2020/08/a-hydrocarbon-c5h10-does-not-react-with.html 2)  https://chemiask.blogspot.com/2020/08/what-are-isomers-of-compound-having.html 3)   https://chemiask.blogspot.com/2020/08/write-equations-for-prepration-of-1.html 4)  https://chemiask.blogspot.com/2020/08/what-are-ambidient-nucleophiles-explain.html 5)  https://chemiask.blogspot.com/2020/08/which-compound-in-each-of-following.html 6)  https://chemiask.blogspot.com/2020/08/predict-all-alkenes-that-would-be.html 7)  https://chemiask.blogspot.com/2020/08/how-will-you-bring-about-following.html
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A Hydrocarbon C5H10 Does Not React With Chlorine In Dark But Gives a Single Monochloro Compound C5H9Cl In Bright Sunlight . Identify The Hydrocarbon .

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A Hydrocarbon with the molecular formula , C5H10 belongs to the group with a General molecular formula CnH2n . Therefore , It May either be an Alkene Or a Cycloalkane . Since Hydrocarbon Does Not React With Chlorine In The Dark , it cannot be an Alkene . Thus it should Be a Cycloalkane .

Further , The Hydrocarbon Gives a Single Monochloro Compound , C5H9Cl By Reacting With Chlorine In Bright Sunlight . Since a Single MonoChloro Compound Is Formed , The Hydrocarbon Must Contain H atoms That Are All Equivalent . Also , As All H Atoms Of A Cycloalkane Are Equivalent , The Hydrocarbon Must Be a Cycloalkane .

Hence  , The Said Compound Is Cyclopentane .
                   CYCLOPENTANE

THE REACTION INVOLVED IN THE QUESTION ARE :


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