NCERT Exercise Solution Of Chemistry (CH1-16) Class-12

(I)   Ethanol To But-1-yne (II) Ethane To Bromoethene (III) Propene To 1-nitropropane (IV) Toluene To Benzyl alcohol (V) Propene To Propene Here Are Only First Five Parts , Next Five Will Be Uploaded In Next Post. Hope It Helps !!   Other Links - You Can Also Visit -  1)  https://chemiask.blogspot.com/2020/08/which-of-following-has-highest-dipole.html 2)   https://chemiask.blogspot.com/2020/08/a-hydrocarbon-c5h10-does-not-react-with.html 3)  https://chemiask.blogspot.com/2020/08/what-are-isomers-of-compound-having.html 4)  https://chemiask.blogspot.com/2020/08/write-equations-for-prepration-of-1.html 5)  https://chemiask.blogspot.com/2020/08/what-are-ambidient-nucleophiles-explain.html 6)  https://chemiask.blogspot.com/2020/08/which-compound-in-each-of-following.html 7)  https://chemiask.blogspot.com/2020/08/predict-all-alkenes-that-would-be.html

Here Is The Answer Of This Question - Alcoholic KOH Is Used As Dehydrogenating Agent. In Each Part Two Alkenes Are Formed , One Of Which One Is Major And Other One Is Minor. Major Alkene Is One In Which Double Bond Lies Between The Carbons Which Are Highly Substituted . Minor Alkene Is One In Which Double Bond Lies Between The Carbons Which Are Not Highly Substituted . (I) 1-Bromo-1-MethylCycloHexane (II) 2-Chloro-2-MethylButane (III) 2,2,3-Trimethyl-3-BromoPentane Other Links :- You May Also Visit - 1) https://chemiask.blogspot.com/2020/08/which-of-following-has-highest-dipole.html 2) https://chemiask.blogspot.com/2020/08/a-hydrocarbon-c5h10-does-not-react-with.html 3) https://chemiask.blogspot.com/2020/08/what-are-isomers-of-compound-having.html 4) https://chemiask.blogspot.com/2020/08/write-equations-for-prepration-of-1.html 5) https://chemiask.blogspot.com/2020/08/what-are-ambidient-nucleophiles-explain.html 6) https://chemiask.blogspot.com/202

(I)   CH3Br Or CH3I (II) (CH3)3CCl Or CH3Cl Answer(I) As   We Know , Rate Determining Factor Of Sterric Hindrances . The Less The Sterric Hindrances Are , More Faster Will Be The SN2 . In This Case Iodine Is Better Leaving Group Than Bromine Because If It's Size . So , CH3I Will React Faster In SN2 Reaction With OH . Answer(II)  As   We Know , Rate Determining Factor Of Sterric Hindrances . The Less The Sterric Hindrances Are , More Faster Will Be The SN2 . So , In Case Of CH3Cl Sterric Hindrances Are Less . So , CH3Cl Will React Faster In SN2 Reaction With OH. Other Links:- You Can Also Visit - 1)  https://chemiask.blogspot.com/2020/08/which-of-following-has-highest-dipole.html 2)  https://chemiask.blogspot.com/2020/08/a-hydrocarbon-c5h10-does-not-react-with.html 3)  https://chemiask.blogspot.com/2020/08/what-are-isomers-of-compound-having.html 4)  https://chemiask.blogspot.com/2020/08/write-equations-for-prepration-of-1.html 5)  https://chemiask.blogspot.com/2020/08/what-are-ambi

AMBIDIENT NUCLEOPHILES Are Nucleophiles Having Two Nucleophilic Sites . Thus , Ambidient Nucleophiles Have Two Sites Through Which They Can Attack . For Example , Nitrite Ion Is An Ambidient Nucleophile .                                    NITRITE ION Nitrite Ion Can Attack Through Oxygen Resulting In The Formation Of Alkyl Nitrites . Also , It Can Attack Through Nitrogen Resulting In The Formation Of Nitroalkanes.                                    ALKYLNITRITE                                  NITROALKANE OTHER LINKS :- You May Also Visit - 1) https://chemiask.blogspot.com/2020/08/which-of-following-has-highest-dipole.html 2) https://chemiask.blogspot.com/2020/08/a-hydrocarbon-c5h10-does-not-react-with.html 3) https://chemiask.blogspot.com/2020/08/what-are-isomers-of-compound-having.html 4) https://chemiask.blogspot.com/2020/08/write-equations-for-prepration-of-1.html AMAZON AD OTHER PRODUCTS YOU MAY LIKE

(I) 1-Butanol To 1-Iodobutane (II) 1-Chlorobutane To 1-Iodobutane (III) But-1-ene To 1-Iodobutane Hope It Helps!! Other Links :- You Can Also Visit - 1) https://chemiask.blogspot.com/2020/08/which-of-following-has-highest-dipole.html 2) https://chemiask.blogspot.com/2020/08/a-hydrocarbon-c5h10-does-not-react-with.html 3) https://chemiask.blogspot.com/2020/08/what-are-isomers-of-compound-having.html             AMAZON AD <

ISOMERS OF COMPOUND HAVING FORMULA C4H9Br                                1-Bromobutane                                2-Bromobutane                     1-Bromo-2-MethylPropane                     2-Bromo-2-MethylPropane Other Links :- You Can Also Visit- 1)  https://chemiask.blogspot.com/?m=1 2) https://chemiask.blogspot.com/?m=2 AMAZON ADVERTISEMENT